b+40=12b-48

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Solution for b+40=12b-48 equation: 



b+40=12b-48

We move all terms to the left:

b+40-(12b-48)=0

We get rid of parentheses

b-12b+48+40=0

We add all the numbers together, and all the variables

-11b+88=0

We move all terms containing b to the left, all other terms to the right

-11b=-88

b=-88/-11

b=+8

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