b+42+2b+47=15b

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Solution for b+42+2b+47=15b equation: 



b+42+2b+47=15b

We move all terms to the left:

b+42+2b+47-(15b)=0

We add all the numbers together, and all the variables

-12b+89=0

We move all terms containing b to the left, all other terms to the right

-12b=-89

b=-89/-12

b=7+5/12

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