b+48=13b+12

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Solution for b+48=13b+12 equation:



b+48=13b+12
We move all terms to the left:
b+48-(13b+12)=0
We get rid of parentheses
b-13b-12+48=0
We add all the numbers together, and all the variables
-12b+36=0
We move all terms containing b to the left, all other terms to the right
-12b=-36
b=-36/-12
b=+3

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