b+48=13b+12

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Solution for b+48=13b+12 equation: 



b+48=13b+12

We move all terms to the left:

b+48-(13b+12)=0

We get rid of parentheses

b-13b-12+48=0

We add all the numbers together, and all the variables

-12b+36=0

We move all terms containing b to the left, all other terms to the right

-12b=-36

b=-36/-12

b=+3

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