b+6/4b+3/2b=b+4/2b

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Solution for b+6/4b+3/2b=b+4/2b equation: 



b+6/4b+3/2b=b+4/2b

We move all terms to the left:

b+6/4b+3/2b-(b+4/2b)=0



Domain of the equation: 4b!=0

b!=0/4

b!=0

b∈R





Domain of the equation: 2b!=0

b!=0/2

b!=0

b∈R





Domain of the equation: 2b)!=0

b!=0/1

b!=0

b∈R



We add all the numbers together, and all the variables

b+6/4b+3/2b-(+b+4/2b)=0

We get rid of parentheses

b+6/4b+3/2b-b-4/2b=0

We calculate fractions


b-b+12b/8b^2+(-16b+3)/8b^2=0

We add all the numbers together, and all the variables

12b/8b^2+(-16b+3)/8b^2=0

We multiply all the terms by the denominator


12b+(-16b+3)=0

We get rid of parentheses

12b-16b+3=0

We add all the numbers together, and all the variables

-4b+3=0

We move all terms containing b to the left, all other terms to the right

-4b=-3

b=-3/-4

b=3/4

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