b+6/4b2+3/2b2=b+4/2b2

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Solution for b+6/4b2+3/2b2=b+4/2b2 equation: 


b in (-oo:+oo)

(6/4)*b^2+(3/2)*b^2+b = (4/2)*b^2+b // - (4/2)*b^2+b

(6/4)*b^2+(3/2)*b^2-((4/2)*b^2)+b-b = 0

(6/4)*b^2+(3/2)*b^2-2*b^2+b-b = 0

1*b^2 = 0 // : 1

b^2 = 0

b = 0

b = 0

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