b+7/2=7b+3/3

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Solution for b+7/2=7b+3/3 equation:



b+7/2=7b+3/3
We move all terms to the left:
b+7/2-(7b+3/3)=0
We add all the numbers together, and all the variables
b-(7b+1)+7/2=0
We get rid of parentheses
b-7b-1+7/2=0
We multiply all the terms by the denominator
b*2-7b*2+7-1*2=0
We add all the numbers together, and all the variables
b*2-7b*2+5=0
Wy multiply elements
2b-14b+5=0
We add all the numbers together, and all the variables
-12b+5=0
We move all terms containing b to the left, all other terms to the right
-12b=-5
b=-5/-12
b=5/12

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