b+b2+b/6=190

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Solution for b+b2+b/6=190 equation: 


b in (-oo:+oo)

b^2+b+b/6 = 190 // - 190

b^2+b+b/6-190 = 0

b^2+7/6*b-190 = 0

DELTA = (7/6)^2-(-190*1*4)

DELTA = 27409/36

DELTA > 0

b = ((27409/36)^(1/2)-7/6)/(1*2) or b = (-(27409/36)^(1/2)-7/6)/(1*2)

b = ((27409/36)^(1/2)-7/6)/2 or b = (-((27409/36)^(1/2)+7/6))/2

b in { (-((27409/36)^(1/2)+7/6))/2, ((27409/36)^(1/2)-7/6)/2 }

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