b+b=2/b-3=2

Solution for b+b=2/b-3=2 equation:

b+b=2/b-3=2

We move all terms to the left:

b+b-(2/b-3)=0


Domain of the equation: b-3)!=0

b∈R


We add all the numbers together, and all the variables

2b-(2/b-3)=0

We get rid of parentheses

2b-2/b+3=0

We multiply all the terms by the denominator


2b*b+3*b-2=0

We add all the numbers together, and all the variables

3b+2b*b-2=0

Wy multiply elements

2b^2+3b-2=0

a = 2; b = 3; c = -2;
Δ = b2-4ac
Δ = 32-4·2·(-2)
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-5}{2*2}=\frac{-8}{4}
=-2
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+5}{2*2}=\frac{2}{4}
=1/2
$