b-(5+4-a)/b

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Solution for b-(5+4-a)/b equation:


x in (-oo:+oo)

b-((4-a+5)/b) = 0

(-1*(9-a))/b+b = 0

(-1*(9-a))/b+(b^2)/b = 0

b^2-1*(9-a) = 0

a+b^2-9 = 0

(a+b^2-9)/b = 0

(a+b^2-9)/b = 0 // * b

a+b^2-9 = 0

x belongs to the empty set

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