b-(b-3b)=5(b-2)

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Solution for b-(b-3b)=5(b-2) equation:


Simplifying
b + -1(b + -3b) = 5(b + -2)

Combine like terms: b + -3b = -2b
b + -1(-2b) = 5(b + -2)

Remove parenthesis around (-2b)
b + -1 * -2b = 5(b + -2)

Multiply -1 * -2
b + 2b = 5(b + -2)

Combine like terms: b + 2b = 3b
3b = 5(b + -2)

Reorder the terms:
3b = 5(-2 + b)
3b = (-2 * 5 + b * 5)
3b = (-10 + 5b)

Solving
3b = -10 + 5b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-5b' to each side of the equation.
3b + -5b = -10 + 5b + -5b

Combine like terms: 3b + -5b = -2b
-2b = -10 + 5b + -5b

Combine like terms: 5b + -5b = 0
-2b = -10 + 0
-2b = -10

Divide each side by '-2'.
b = 5

Simplifying
b = 5

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