b-0.5(10-6b)=2(0.5b-7)

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Solution for b-0.5(10-6b)=2(0.5b-7) equation:



b-0.5(10-6b)=2(0.5b-7)
We move all terms to the left:
b-0.5(10-6b)-(2(0.5b-7))=0
We add all the numbers together, and all the variables
b-0.5(-6b+10)-(2(0.5b-7))=0
We multiply parentheses
b+3b-(2(0.5b-7))-5=0
We calculate terms in parentheses: -(2(0.5b-7)), so:
2(0.5b-7)
We multiply parentheses
0b-14
We add all the numbers together, and all the variables
b-14
Back to the equation:
-(b-14)
We add all the numbers together, and all the variables
4b-(b-14)-5=0
We get rid of parentheses
4b-b+14-5=0
We add all the numbers together, and all the variables
3b+9=0
We move all terms containing b to the left, all other terms to the right
3b=-9
b=-9/3
b=-3

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