b-1/4b=6

Solution for b-1/4b=6 equation:

b-1/4b=6

We move all terms to the left:

b-1/4b-(6)=0


Domain of the equation: 4b!=0

b!=0/4

b!=0

b∈R


We multiply all the terms by the denominator


b*4b-6*4b-1=0

Wy multiply elements

4b^2-24b-1=0

a = 4; b = -24; c = -1;
Δ = b2-4ac
Δ = -242-4·4·(-1)
Δ = 592
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{592}=\sqrt{16*37}=\sqrt{16}*\sqrt{37}=4\sqrt{37}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-4\sqrt{37}}{2*4}=\frac{24-4\sqrt{37}}{8}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+4\sqrt{37}}{2*4}=\frac{24+4\sqrt{37}}{8}
$