b-12=3;b=

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Solution for b-12=3;b= equation: 



b-12=3b=

We move all terms to the left:

b-12-(3b)=0

We add all the numbers together, and all the variables

-2b-12=0

We move all terms containing b to the left, all other terms to the right

-2b=12

b=12/-2

b=-6

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