b-13=3(1-b)+4

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Solution for b-13=3(1-b)+4 equation: 



b-13=3(1-b)+4

We move all terms to the left:

b-13-(3(1-b)+4)=0

We add all the numbers together, and all the variables

b-(3(-1b+1)+4)-13=0



We calculate terms in parentheses: -(3(-1b+1)+4), so:

3(-1b+1)+4

We multiply parentheses

-3b+3+4

We add all the numbers together, and all the variables

-3b+7

Back to the equation:

-(-3b+7)



We get rid of parentheses

b+3b-7-13=0

We add all the numbers together, and all the variables

4b-20=0

We move all terms containing b to the left, all other terms to the right

4b=20

b=20/4

b=5

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