b-2(1+12b)=2(8-12b)

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Solution for b-2(1+12b)=2(8-12b) equation:



b-2(1+12b)=2(8-12b)
We move all terms to the left:
b-2(1+12b)-(2(8-12b))=0
We add all the numbers together, and all the variables
b-2(12b+1)-(2(-12b+8))=0
We multiply parentheses
b-24b-(2(-12b+8))-2=0
We calculate terms in parentheses: -(2(-12b+8)), so:
2(-12b+8)
We multiply parentheses
-24b+16
Back to the equation:
-(-24b+16)
We add all the numbers together, and all the variables
-23b-(-24b+16)-2=0
We get rid of parentheses
-23b+24b-16-2=0
We add all the numbers together, and all the variables
b-18=0
We move all terms containing b to the left, all other terms to the right
b=18

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