b-2(1+c-b)=

Solution for b-2(1+c-b)= equation:

Simplifying
b + -2(1 + c + -1b) = 0

Reorder the terms:
b + -2(1 + -1b + c) = 0
b + (1 * -2 + -1b * -2 + c * -2) = 0
b + (-2 + 2b + -2c) = 0

Reorder the terms:
-2 + b + 2b + -2c = 0

Combine like terms: b + 2b = 3b
-2 + 3b + -2c = 0

Solving
-2 + 3b + -2c = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 3b + 2 + -2c = 0 + 2

Reorder the terms:
-2 + 2 + 3b + -2c = 0 + 2

Combine like terms: -2 + 2 = 0
0 + 3b + -2c = 0 + 2
3b + -2c = 0 + 2

Combine like terms: 0 + 2 = 2
3b + -2c = 2

Add '2c' to each side of the equation.
3b + -2c + 2c = 2 + 2c

Combine like terms: -2c + 2c = 0
3b + 0 = 2 + 2c
3b = 2 + 2c

Divide each side by '3'.
b = 0.6666666667 + 0.6666666667c

Simplifying
b = 0.6666666667 + 0.6666666667c