b-2(5-b)=2

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Solution for b-2(5-b)=2 equation: 



b-2(5-b)=2

We move all terms to the left:

b-2(5-b)-(2)=0

We add all the numbers together, and all the variables

b-2(-1b+5)-2=0

We multiply parentheses

b+2b-10-2=0

We add all the numbers together, and all the variables

3b-12=0

We move all terms containing b to the left, all other terms to the right

3b=12

b=12/3

b=4

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