b-2(b+3)=40

Solution for b-2(b+3)=40 equation:

Simplifying
b + -2(b + 3) = 40

Reorder the terms:
b + -2(3 + b) = 40
b + (3 * -2 + b * -2) = 40
b + (-6 + -2b) = 40

Reorder the terms:
-6 + b + -2b = 40

Combine like terms: b + -2b = -1b
-6 + -1b = 40

Solving
-6 + -1b = 40

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '6' to each side of the equation.
-6 + 6 + -1b = 40 + 6

Combine like terms: -6 + 6 = 0
0 + -1b = 40 + 6
-1b = 40 + 6

Combine like terms: 40 + 6 = 46
-1b = 46

Divide each side by '-1'.
b = -46

Simplifying
b = -46