b-2(b-15)=5b

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Solution for b-2(b-15)=5b equation: 



b-2(b-15)=5b

We move all terms to the left:

b-2(b-15)-(5b)=0

We add all the numbers together, and all the variables

-4b-2(b-15)=0

We multiply parentheses

-4b-2b+30=0

We add all the numbers together, and all the variables

-6b+30=0

We move all terms containing b to the left, all other terms to the right

-6b=-30

b=-30/-6

b=+5

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