b-2(b-15)=5b

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Solution for b-2(b-15)=5b equation:



b-2(b-15)=5b
We move all terms to the left:
b-2(b-15)-(5b)=0
We add all the numbers together, and all the variables
-4b-2(b-15)=0
We multiply parentheses
-4b-2b+30=0
We add all the numbers together, and all the variables
-6b+30=0
We move all terms containing b to the left, all other terms to the right
-6b=-30
b=-30/-6
b=+5

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