b-2(b-18)=3b

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Solution for b-2(b-18)=3b equation: 



b-2(b-18)=3b

We move all terms to the left:

b-2(b-18)-(3b)=0

We add all the numbers together, and all the variables

-2b-2(b-18)=0

We multiply parentheses

-2b-2b+36=0

We add all the numbers together, and all the variables

-4b+36=0

We move all terms containing b to the left, all other terms to the right

-4b=-36

b=-36/-4

b=+9

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