b-2(b-2)=3(b+5)+1

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Solution for b-2(b-2)=3(b+5)+1 equation: 


Simplifying
b + -2(b + -2) = 3(b + 5) + 1

Reorder the terms:
b + -2(-2 + b) = 3(b + 5) + 1
b + (-2 * -2 + b * -2) = 3(b + 5) + 1
b + (4 + -2b) = 3(b + 5) + 1

Reorder the terms:
4 + b + -2b = 3(b + 5) + 1

Combine like terms: b + -2b = -1b
4 + -1b = 3(b + 5) + 1

Reorder the terms:
4 + -1b = 3(5 + b) + 1
4 + -1b = (5 * 3 + b * 3) + 1
4 + -1b = (15 + 3b) + 1

Reorder the terms:
4 + -1b = 15 + 1 + 3b

Combine like terms: 15 + 1 = 16
4 + -1b = 16 + 3b

Solving
4 + -1b = 16 + 3b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-3b' to each side of the equation.
4 + -1b + -3b = 16 + 3b + -3b

Combine like terms: -1b + -3b = -4b
4 + -4b = 16 + 3b + -3b

Combine like terms: 3b + -3b = 0
4 + -4b = 16 + 0
4 + -4b = 16

Add '-4' to each side of the equation.
4 + -4 + -4b = 16 + -4

Combine like terms: 4 + -4 = 0
0 + -4b = 16 + -4
-4b = 16 + -4

Combine like terms: 16 + -4 = 12
-4b = 12

Divide each side by '-4'.
b = -3

Simplifying
b = -3

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