b-2=1+b/20

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Solution for b-2=1+b/20 equation: 



b-2=1+b/20

We move all terms to the left:

b-2-(1+b/20)=0

We add all the numbers together, and all the variables

b-(b/20+1)-2=0

We get rid of parentheses

b-b/20-1-2=0

We multiply all the terms by the denominator


b*20-b-1*20-2*20=0

We add all the numbers together, and all the variables

-1b+b*20-60=0

Wy multiply elements

-1b+20b-60=0

We add all the numbers together, and all the variables

19b-60=0

We move all terms containing b to the left, all other terms to the right

19b=60

b=60/19

b=3+3/19

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