b-2=1+b/20

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Solution for b-2=1+b/20 equation:



b-2=1+b/20
We move all terms to the left:
b-2-(1+b/20)=0
We add all the numbers together, and all the variables
b-(b/20+1)-2=0
We get rid of parentheses
b-b/20-1-2=0
We multiply all the terms by the denominator
b*20-b-1*20-2*20=0
We add all the numbers together, and all the variables
-1b+b*20-60=0
Wy multiply elements
-1b+20b-60=0
We add all the numbers together, and all the variables
19b-60=0
We move all terms containing b to the left, all other terms to the right
19b=60
b=60/19
b=3+3/19

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