b-2=1+b/4

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Solution for b-2=1+b/4 equation: 



b-2=1+b/4

We move all terms to the left:

b-2-(1+b/4)=0

We add all the numbers together, and all the variables

b-(b/4+1)-2=0

We get rid of parentheses

b-b/4-1-2=0

We multiply all the terms by the denominator


b*4-b-1*4-2*4=0

We add all the numbers together, and all the variables

-1b+b*4-12=0

Wy multiply elements

-1b+4b-12=0

We add all the numbers together, and all the variables

3b-12=0

We move all terms containing b to the left, all other terms to the right

3b=12

b=12/3

b=4

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