b-3(1-3b)=-27+2b

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Solution for b-3(1-3b)=-27+2b equation: 



b-3(1-3b)=-27+2b

We move all terms to the left:

b-3(1-3b)-(-27+2b)=0

We add all the numbers together, and all the variables

b-3(-3b+1)-(2b-27)=0

We multiply parentheses

b+9b-(2b-27)-3=0

We get rid of parentheses

b+9b-2b+27-3=0

We add all the numbers together, and all the variables

8b+24=0

We move all terms containing b to the left, all other terms to the right

8b=-24

b=-24/8

b=-3

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