b-3(b+(4/3))=2b+3

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Solution for b-3(b+(4/3))=2b+3 equation: 


b in (-oo:+oo)

b-(3*(b+4/3)) = 2*b+3 // - 2*b+3

b-(3*(b+4/3))-(2*b)-3 = 0

b-3*(b+4/3)-2*b-3 = 0

b-3*(b+4/3)-2*b-3 = 0

-2*b-2*b-4-3 = 0

-4*b-4-3 = 0

-4*b-7 = 0

-4*b-7 = 0

-4*b-7 = 0 // + 7

-4*b = 7 // : -4

b = 7/(-4)

b = -7/4

b = -7/4

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