b-3(b+1)=1-(4b-1)

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Solution for b-3(b+1)=1-(4b-1) equation: 



b-3(b+1)=1-(4b-1)

We move all terms to the left:

b-3(b+1)-(1-(4b-1))=0

We multiply parentheses

b-3b-(1-(4b-1))-3=0



We calculate terms in parentheses: -(1-(4b-1)), so:

1-(4b-1)

determiningTheFunctionDomain
-(4b-1)+1

We get rid of parentheses

-4b+1+1

We add all the numbers together, and all the variables

-4b+2

Back to the equation:

-(-4b+2)



We add all the numbers together, and all the variables

-2b-(-4b+2)-3=0

We get rid of parentheses

-2b+4b-2-3=0

We add all the numbers together, and all the variables

2b-5=0

We move all terms containing b to the left, all other terms to the right

2b=5

b=5/2

b=2+1/2

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