b-3+(3b)=28

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Solution for b-3+(3b)=28 equation: 



b-3+(3b)=28

We move all terms to the left:

b-3+(3b)-(28)=0

We add all the numbers together, and all the variables

4b-31=0

We move all terms containing b to the left, all other terms to the right

4b=31

b=31/4

b=7+3/4

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