b-3/b-8

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Solution for b-3/b-8 equation: 


D( b )

b = 0

b = 0

b = 0

b in (-oo:0) U (0:+oo)

b-(3/b)-8 = 0

b-3*b^-1-8 = 0

1*b^1-3*b^-1-8*b^0 = 0

(1*b^2-8*b^1-3*b^0)/(b^1) = 0 // * b^2

b^1*(1*b^2-8*b^1-3*b^0) = 0

b^1

b^2-8*b-3 = 0

b^2-8*b-3 = 0

DELTA = (-8)^2-(-3*1*4)

DELTA = 76

DELTA > 0

b = (76^(1/2)+8)/(1*2) or b = (8-76^(1/2))/(1*2)

b = (2*19^(1/2)+8)/2 or b = (8-2*19^(1/2))/2

b in { (8-2*19^(1/2))/2, (2*19^(1/2)+8)/2} 

b in { (8-2*19^(1/2))/2, (2*19^(1/2)+8)/2 }

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