b-4(2b+5)=29

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Solution for b-4(2b+5)=29 equation: 



b-4(2b+5)=29

We move all terms to the left:

b-4(2b+5)-(29)=0

We multiply parentheses

b-8b-20-29=0

We add all the numbers together, and all the variables

-7b-49=0

We move all terms containing b to the left, all other terms to the right

-7b=49

b=49/-7

b=-7

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