b-4-2=8-(9+b)

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Solution for b-4-2=8-(9+b) equation: 



b-4-2=8-(9+b)

We move all terms to the left:

b-4-2-(8-(9+b))=0

We add all the numbers together, and all the variables

b-(8-(b+9))-4-2=0

We add all the numbers together, and all the variables

b-(8-(b+9))-6=0



We calculate terms in parentheses: -(8-(b+9)), so:

8-(b+9)

determiningTheFunctionDomain
-(b+9)+8

We get rid of parentheses

-b-9+8

We add all the numbers together, and all the variables

-1b-1

Back to the equation:

-(-1b-1)



We get rid of parentheses

b+1b+1-6=0

We add all the numbers together, and all the variables

2b-5=0

We move all terms containing b to the left, all other terms to the right

2b=5

b=5/2

b=2+1/2

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