b-4=3(b+2)

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Solution for b-4=3(b+2) equation:


Simplifying
b + -4 = 3(b + 2)

Reorder the terms:
-4 + b = 3(b + 2)

Reorder the terms:
-4 + b = 3(2 + b)
-4 + b = (2 * 3 + b * 3)
-4 + b = (6 + 3b)

Solving
-4 + b = 6 + 3b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-3b' to each side of the equation.
-4 + b + -3b = 6 + 3b + -3b

Combine like terms: b + -3b = -2b
-4 + -2b = 6 + 3b + -3b

Combine like terms: 3b + -3b = 0
-4 + -2b = 6 + 0
-4 + -2b = 6

Add '4' to each side of the equation.
-4 + 4 + -2b = 6 + 4

Combine like terms: -4 + 4 = 0
0 + -2b = 6 + 4
-2b = 6 + 4

Combine like terms: 6 + 4 = 10
-2b = 10

Divide each side by '-2'.
b = -5

Simplifying
b = -5

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