b-5(b+1)-3=-(8+4b)

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Solution for b-5(b+1)-3=-(8+4b) equation: 



b-5(b+1)-3=-(8+4b)

We move all terms to the left:

b-5(b+1)-3-(-(8+4b))=0

We add all the numbers together, and all the variables

b-5(b+1)-(-(4b+8))-3=0

We multiply parentheses

b-5b-(-(4b+8))-5-3=0



We calculate terms in parentheses: -(-(4b+8)), so:

-(4b+8)

We get rid of parentheses

-4b-8

Back to the equation:

-(-4b-8)



We add all the numbers together, and all the variables

-4b-(-4b-8)-8=0

We get rid of parentheses

-4b+4b+8-8=0

We add all the numbers together, and all the variables

=0

b=0/1

b=0

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