b-5-12=12(b+9)+3(b-3)

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Solution for b-5-12=12(b+9)+3(b-3) equation:


b-5-12=12(b+9)+3(b-3)

We simplify the equation to the form, which is simple to understand 
b-5-12=12(b+9)+3(b-3)

Reorder the terms in parentheses
b-5-12=+(+12b+108)+3*(b-3)

Remove unnecessary parentheses
+b-5-12=+12b+108+3+*(+b-3+)

Reorder the terms in parentheses
b-5-12=+12b+108+(+3b-9)

Remove unnecessary parentheses
+b-5-12=+12b+108+3b-9

We move all terms containing b to the left and all other terms to the right. 
+1b-12b-3b=+108-9+5+12

We simplify left and right side of the equation. 
-14b=+116

We divide both sides of the equation by -14 to get b. 
b=-8.2857142857143

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