b-6/3=b+5/2 - solution

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Solution for b-6/3=b+5/2 equation:

b in (-oo:+oo)

b-(6/3) = b+5/2 // - b+5/2

b-b-(6/3)-(5/2) = 0

b-b-5/2-2 = 0

-9/2 = 0

b belongs to the empty set

b belongs to the empty set

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