b-6=2b2-3

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Solution for b-6=2b2-3 equation: 



b-6=2b^2-3

We move all terms to the left:

b-6-(2b^2-3)=0

We get rid of parentheses

-2b^2+b+3-6=0

We add all the numbers together, and all the variables

-2b^2+b-3=0

a = -2; b = 1; c = -3;
Δ = b2-4ac
Δ = 12-4·(-2)·(-3)
Δ = -23
Delta is less than zero, so there is no solution for the equation

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