b-7(6+3b)=-122

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Solution for b-7(6+3b)=-122 equation: 



b-7(6+3b)=-122

We move all terms to the left:

b-7(6+3b)-(-122)=0

We add all the numbers together, and all the variables

b-7(3b+6)-(-122)=0

We add all the numbers together, and all the variables

b-7(3b+6)+122=0

We multiply parentheses

b-21b-42+122=0

We add all the numbers together, and all the variables

-20b+80=0

We move all terms containing b to the left, all other terms to the right

-20b=-80

b=-80/-20

b=+4

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