b-7=2b-3(4b+1)+-4

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Solution for b-7=2b-3(4b+1)+-4 equation: 



b-7=2b-3(4b+1)+-4

We move all terms to the left:

b-7-(2b-3(4b+1)+-4)=0

We use the square of the difference formula

b-(2b-3(4b+1)-4)-7=0



We calculate terms in parentheses: -(2b-3(4b+1)-4), so:

2b-3(4b+1)-4

We multiply parentheses

2b-12b-3-4

We add all the numbers together, and all the variables

-10b-7

Back to the equation:

-(-10b-7)



We get rid of parentheses

b+10b+7-7=0

We add all the numbers together, and all the variables

11b=0

b=0/11

b=0

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