b-8(b-4)=-6b+40

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Solution for b-8(b-4)=-6b+40 equation: 



b-8(b-4)=-6b+40

We move all terms to the left:

b-8(b-4)-(-6b+40)=0

We multiply parentheses

b-8b-(-6b+40)+32=0

We get rid of parentheses

b-8b+6b-40+32=0

We add all the numbers together, and all the variables

-1b-8=0

We move all terms containing b to the left, all other terms to the right

-b=8

b=8/-1

b=-8

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