b-8+4b-6=-2(b+5)+2(b-2)

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Solution for b-8+4b-6=-2(b+5)+2(b-2) equation: 



b-8+4b-6=-2(b+5)+2(b-2)

We move all terms to the left:

b-8+4b-6-(-2(b+5)+2(b-2))=0

We add all the numbers together, and all the variables

5b-(-2(b+5)+2(b-2))-14=0



We calculate terms in parentheses: -(-2(b+5)+2(b-2)), so:

-2(b+5)+2(b-2)

We multiply parentheses

-2b+2b-10-4

We add all the numbers together, and all the variables

-14

Back to the equation:

-(-14)



We add all the numbers together, and all the variables

5b=0

b=0/5

b=0

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