b-9=1-5(b+2)

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Solution for b-9=1-5(b+2) equation: 



b-9=1-5(b+2)

We move all terms to the left:

b-9-(1-5(b+2))=0



We calculate terms in parentheses: -(1-5(b+2)), so:

1-5(b+2)

determiningTheFunctionDomain
-5(b+2)+1

We multiply parentheses

-5b-10+1

We add all the numbers together, and all the variables

-5b-9

Back to the equation:

-(-5b-9)



We get rid of parentheses

b+5b+9-9=0

We add all the numbers together, and all the variables

6b=0

b=0/6

b=0

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