b/11=3;b=33

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Solution for b/11=3;b=33 equation:



b/11=3b=33
We move all terms to the left:
b/11-(3b)=0
We add all the numbers together, and all the variables
-3b+b/11=0
We multiply all the terms by the denominator
-3b*11+b=0
We add all the numbers together, and all the variables
b-3b*11=0
Wy multiply elements
b-33b=0
We add all the numbers together, and all the variables
-32b=0
b=0/-32
b=0

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