b/12=6;b=72

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Solution for b/12=6;b=72 equation: 



b/12=6b=72

We move all terms to the left:

b/12-(6b)=0

We add all the numbers together, and all the variables

-6b+b/12=0

We multiply all the terms by the denominator


-6b*12+b=0

We add all the numbers together, and all the variables

b-6b*12=0

Wy multiply elements

b-72b=0

We add all the numbers together, and all the variables

-71b=0

b=0/-71

b=0

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