b/2+b+b+5+b2-3=47

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Solution for b/2+b+b+5+b2-3=47 equation: 


b in (-oo:+oo)

b^2+b/2+b+b-3+5 = 47 // - 47

b^2+b/2+b+b-47-3+5 = 0

b^2+5/2*b-45 = 0

DELTA = (5/2)^2-(-45*1*4)

DELTA = 745/4

DELTA > 0

b = ((745/4)^(1/2)-5/2)/(1*2) or b = (-(745/4)^(1/2)-5/2)/(1*2)

b = ((745/4)^(1/2)-5/2)/2 or b = (-((745/4)^(1/2)+5/2))/2

b in { (-((745/4)^(1/2)+5/2))/2, ((745/4)^(1/2)-5/2)/2 }

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