b/4-6=3b/4-19

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Solution for b/4-6=3b/4-19 equation: 



b/4-6=3b/4-19

We move all terms to the left:

b/4-6-(3b/4-19)=0

We get rid of parentheses

b/4-3b/4+19-6=0

We multiply all the terms by the denominator


b-3b+19*4-6*4=0

We add all the numbers together, and all the variables

-2b+52=0

We move all terms containing b to the left, all other terms to the right

-2b=-52

b=-52/-2

b=+26

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