b/5+-3=2

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Solution for b/5+-3=2 equation: 



b/5+-3=2

We move all terms to the left:

b/5+-3-(2)=0

determiningTheFunctionDomain
b/5-3-2+=0

We add all the numbers together, and all the variables

b/5=0

We multiply all the terms by the denominator


b=0

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