b2+3+2b2+4=7

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Solution for b2+3+2b2+4=7 equation: 



b2+3+2b^2+4=7

We move all terms to the left:

b2+3+2b^2+4-(7)=0

We add all the numbers together, and all the variables

3b^2=0

a = 3; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·3·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$b=\frac{-b}{2a}=\frac{0}{6}=0$

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