b2+4/5b=-1/5

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Solution for b2+4/5b=-1/5 equation: 


b in (-oo:+oo)

b^2+(4/5)*b = -1/5 // + -1/5

b^2+(4/5)*b-(-1/5) = 0

b^2+(4/5)*b+1/5 = 0

b^2+4/5*b+1/5 = 0

DELTA = (4/5)^2-(1/5*1*4)

DELTA = -4/25

DELTA < 0

b belongs to the empty set

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