b2-6b-59=-4b+4

Solution for b2-6b-59=-4b+4 equation:

b2-6b-59=-4b+4

We move all terms to the left:

b2-6b-59-(-4b+4)=0

We add all the numbers together, and all the variables

b^2-6b-(-4b+4)-59=0

We get rid of parentheses

b^2-6b+4b-4-59=0

We add all the numbers together, and all the variables

b^2-2b-63=0

a = 1; b = -2; c = -63;
Δ = b2-4ac
Δ = -22-4·1·(-63)
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-16}{2*1}=\frac{-14}{2}
=-7
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+16}{2*1}=\frac{18}{2}
=9
$