b2/4+35=61

Solution for b2/4+35=61 equation:

b2/4+35=61

We move all terms to the left:

b2/4+35-(61)=0

We add all the numbers together, and all the variables

b2/4-26=0

We multiply all the terms by the denominator


b2-26*4=0

We add all the numbers together, and all the variables

b^2-104=0

a = 1; b = 0; c = -104;
Δ = b2-4ac
Δ = 02-4·1·(-104)
Δ = 416
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{416}=\sqrt{16*26}=\sqrt{16}*\sqrt{26}=4\sqrt{26}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{26}}{2*1}=\frac{0-4\sqrt{26}}{2}
=-\frac{4\sqrt{26}}{2}
=-2\sqrt{26}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{26}}{2*1}=\frac{0+4\sqrt{26}}{2}
=\frac{4\sqrt{26}}{2}
=2\sqrt{26}
$