b2=12116

Solution for b2=12116 equation:

b2=12116

We move all terms to the left:

b2-(12116)=0

We add all the numbers together, and all the variables

b^2-12116=0

a = 1; b = 0; c = -12116;
Δ = b2-4ac
Δ = 02-4·1·(-12116)
Δ = 48464
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{48464}=\sqrt{16*3029}=\sqrt{16}*\sqrt{3029}=4\sqrt{3029}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{3029}}{2*1}=\frac{0-4\sqrt{3029}}{2}
=-\frac{4\sqrt{3029}}{2}
=-2\sqrt{3029}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{3029}}{2*1}=\frac{0+4\sqrt{3029}}{2}
=\frac{4\sqrt{3029}}{2}
=2\sqrt{3029}
$